the amount of sulfuric acid which contains 6.02*10^23 of oxygen
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Answered by
1
6.02*10^23=1 mol
so 4 atoms contains 1 mol
=0.25 mol of sulphuric acid
2+32+64=98/4. (.25=1/4)
14.5g
so 4 atoms contains 1 mol
=0.25 mol of sulphuric acid
2+32+64=98/4. (.25=1/4)
14.5g
Answered by
1
HEY FRIEND HERE YOUR ANSWER
(6.02 x 10^23 atoms O) / (6.02 x 10^23 atoms/mol) x (1 mol H2SO4 / 4 mol O) x (98.0791 g H2SO4/mol) =
24.5 g H2SO4
I HOPE IT'S HELP YOU
MARK BRAINLIEST MY ANSWER DEAR FRIEND
(6.02 x 10^23 atoms O) / (6.02 x 10^23 atoms/mol) x (1 mol H2SO4 / 4 mol O) x (98.0791 g H2SO4/mol) =
24.5 g H2SO4
I HOPE IT'S HELP YOU
MARK BRAINLIEST MY ANSWER DEAR FRIEND
tinu21:
mark BRAINLIEST my answer
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