The amount of water of mass 20 gm at 0°C mixed with 40 gm of water at 10°С. Find
temperature of the mixture is
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Answer:
The temperature of the mixture is 6.666...
Explanation:
Heat lost by water at 10 degrees = Heat gained by water at 0 degrees
Q = m*c*change in temp.
20 * 4.2 * T = 40 * 4.2 * (10 - T)
T = 2(10-T)
T = 20 - 2T
3T = 20
T = 20/3 = 6.666...
Therefore, the final temperature is 6.666...
Hope this helped you !
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