The amount of water that should be added to 500 ml of 0.5 n solution of naoh to give a concentration of 10 mg per ml is
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Answer:
1000 ml
Explanation:
Quantity of solution = 500ml (Given)
Strength of Naoh = 10mg (Given)
Strength = Molarity × Molarmass
Thus, 10/l = Molarity/40mg
Therefore, the molarity = 0.25
Using the equation of molarity = M1V1 = M2V2
where M1 is the Molarity of first solution, V1 is the Volume of first solution, M2 is the Molarity of second solution and V2 is the Volume of second solution.
Hence,
0.5M × 500ml
=0.25 × V2mlV2
= 1000 ml
Thus, the amount of water that should be added to the Naoh solution is 1000ml.
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