Question

The amount of wheat in tons coming from Bhopal to Delhi is given below.
Amt, of wheat (in ) No. of days
21-25 7
26-30 13
31-35 22
36-40 10
41-45 8
Find the mode.​

Answer 1

The answer is 21-25 7 mark as brainliest

Answer 2

Given are the Frequency distribution for the amount of wheat and the number of days, Find the mode of the distribution.

Explanation:

• The table for the frequency distribution of wheat coming from Bhopal to Delhi along with their corresponding cumulative frequencies is,
• $Amt. \ of\ wheat\ \ \ \ \ No.\ of\ days\ \ \ \ \ \ cf \\21-25\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 7\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 7 \\26-30\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 13\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 20\\31-35\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 22\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 42 \\36-40\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 10\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 52 \\41-45\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 8\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 60$  
• The modal class of the data is the class having the highest frequency that is, $31-35$
• The class size of the data is $C=5$.
• Now the mode of the data using obtained modal class can be given by, $M_o=L+(\frac{f_m-f_1}{2f_m-f_1-f_2}) C$
• 'L'- lower bound of modal class
• 'f1' and 'f2' -frequencies of classes preceding and succeeding modal class
• 'fm' - frequency of modal class.  
• Hence, the mode is,
• $M_o=31+(\frac{22-13}{44-13-10})5 \\->M_o=31+2.143\\->M_o=33.143$
• The mode amount of wheat from the data is $33.143\ tons$ (approx.).