Question

The amount of work done in bringing 0.01 C of charge is 8 joule . How much is the potential difference .

Answer 1

Answer:

800joule

Explanation:

p.d=w/q

w -work done

q-charge

Answer 2

Answer: 800J of work done

Explanation:

Since ∆V=work done /charge

So, by putting values we get,

∆V=8/0.01

∆V=800Joules

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