The amount of work done in bringing charge of 1.3×10^-7 coulomb from infinity to a point in an electric field is 6.5×10^-5 joule. find the electric potential at the point.
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Answered by
52
Hey friend
here is your answer
charge ( Q )= 1.3 × 10^-7
work ( W ) = 6.5 × 10^-5
electric potential ( v ) = ? ( to find )
as

glad to help you
hope it helps
thank you.
here is your answer
charge ( Q )= 1.3 × 10^-7
work ( W ) = 6.5 × 10^-5
electric potential ( v ) = ? ( to find )
as
glad to help you
hope it helps
thank you.
Answered by
8
Answer:
sl
here is your answer
Explanation:
see it
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