The amount of work done in forming a soap film of
size 5 cm x 15 cm if surface tension is 10-2 N/m
Answers
Answered by
2
Answer:
Explanation:
Generally
Work = Force * Displacement OR
Work = Surface Tension * Change in Surface Area
But a bubble has two surfaces- the outer and inner Surface, hence
change in Surface Area will be 2 (5 - 2 ) = 2 * 3 cm² = 6 cm²
Work = 0.06 N/m * 6 cm² = 0.06 N/m * 6 (10^-2)² m².
Work = 36 * 10^-6 Joule
Similar questions
Computer Science,
5 months ago
Computer Science,
9 months ago
Math,
9 months ago
Math,
11 months ago
English,
11 months ago