The amount of work done in increasing the voltage across the plates of a capacitor from 5 V to 10 V is W.
The workdone in increasing it from 10 V to 15 V is
Answers
The expression for the work done in terms of charge and potential difference is as follows;
w=q\Delta Vw=qΔV .......... (1)
Here, q is the charge and \Delta VΔV is the change in the potential.
It is given in the problem that The amount of work done in increasing the voltage across the plates of capacitor from 5v to 10v is w.
Calculate the change in potential.
\Delta V= 10 V - 5 VΔV=10V−5V
\Delta V= 5 VΔV=5V
Put \Delta V= 5 VΔV=5V in the expression (1).
w=q(5)w=q(5) ....... (2)
Calculate the change in potential from 10V to 15V.
\Delta V= 15 V - 10 VΔV=15V−10V
\Delta V= 5 VΔV=5V
Calculate the work done in increasing it from 10 V to 15 V by using the expression (1).
w'=5qw
′
=5q
Put 5q=w by using equation (2).
w'=ww
′
=w
Therefore, the correct option is (a)
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