Physics, asked by gagrashar156, 1 year ago

The amount of work done on an object when a constant force 1/10 N displaces it by 10 cm along the line of action of force is. 1 :- 1/100 J. 2:- 1/10 J. 3:- 10J. 4:- 1 J

Answers

Answered by Anonymous
13
work done = force X displacement

units must be same...so convert cm into m

work done = 1/10 X 10/100

= 1/100

0ptiin (1) is correct. ..

HOPE IT WILL HELP YOU
Answered by sonalmishra
3

The answer is 0.01 J

The answer is in attachment

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