Physics, asked by aastha4174, 1 year ago

The amount of work required to take a charge of 10 C from point A at potential 4 V to a point
B at potential 12 V is
(a) 160 J
80J
(c) 40 J
120 J​

Answers

Answered by ajr111
1

Answer:

W=80J

Explanation:

V2=12V          

V1=4V

Q=10C

W=?

V2-V1=W/Q

12-4=W/10

8*10=W

W=80J

Hope it helps.........

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