Question

The amount of zinc required to produce 1.12 ml of h2 at STP on treatment with dilute HCl will be?

Answer 1

The balanced chemical equation is,

Zn + 2 HCl -----------> ZnCl₂ + H₂

So, 1 mole of Zn will produce 1 mole of H₂, which is 22,400 ml.

Number of moles of H₂ in 1.12 ml = 1.12/22400 = 5 x 10⁻⁵

So, 5 x 10⁻⁵ moles of Zn is required.

Mass of 5 x 10⁻⁵ moles of Zn = 5 x 10⁻⁵ x atomic mass

= 5 x 10⁻⁵ x 65

= 3.25 x 10⁻³ grams of Zn is formed.

Hope it helps!!