the amount of zinc required to produce 1.12 ml of hydrogen gas at STP on treatment with dilute hcl will be
Answers
Answered by
0
ZN +2 HCL ============> ZNCL2 + H2
BY STOICHIOMETRIC CALCULATIONS
FROM 1 MOLE OF ZN WE GET 2 MOLES OF H2............ (1)
MOLES OF H2 = 11.2/222.4= 0.5 MOLES
WE KNOW THAT A GAS OCCUPIES 22.4L AT S.T.P
NOW SO MOLES OF ZN WILL BE HALF OF THAT OF HCL from (1)
MOLES OF ZN = 0.25
AMOUNT OF ZN = 1/4 × 65.38 = 16.345
THANK U★★★
#CKC
BY STOICHIOMETRIC CALCULATIONS
FROM 1 MOLE OF ZN WE GET 2 MOLES OF H2............ (1)
MOLES OF H2 = 11.2/222.4= 0.5 MOLES
WE KNOW THAT A GAS OCCUPIES 22.4L AT S.T.P
NOW SO MOLES OF ZN WILL BE HALF OF THAT OF HCL from (1)
MOLES OF ZN = 0.25
AMOUNT OF ZN = 1/4 × 65.38 = 16.345
THANK U★★★
#CKC
Similar questions