Question

the amount of zinc required to produce 1.12 ml of hydrogen gas at STP on treatment with dilute hcl will be

Answer 1

ZN +2 HCL ============> ZNCL2 + H2

BY STOICHIOMETRIC CALCULATIONS

FROM 1 MOLE OF ZN WE GET 2 MOLES OF H2............ (1)

MOLES OF H2 = 11.2/222.4= 0.5 MOLES


WE KNOW THAT A GAS OCCUPIES 22.4L AT S.T.P

NOW SO MOLES OF ZN WILL BE HALF OF THAT OF HCL from (1)

MOLES OF ZN = 0.25

AMOUNT OF ZN = 1/4 × 65.38 = 16.345

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