Question

the amount of zinc required to produce 224 ml of H2 at STP on treatment with dilute H2 S o4 will be how to do this question with equivalent mass concept​

Answer 1

Answer:

65 g. B.

5 g. C.

65 g. D.

065 g. Medium. Solution. Verified by Toppr. A.

65 g. Zn+H2SO4→ZnSO4+H2 At STP 224 mL of hydrogen corresponds to 1000×22. 4224=0. 01 moles of hydrogen. They will be produced from the reaction of 0.01 mole of Zn with 0.01 mole of sulphuric acid. Hence, the mass of zinc required is 65. 38×0. 01=0. 65 g.

Answer 2

Explanation:

the amount of zinc required to produce 224 ml of H2 at STP on treatment with dilute H2 S o4 will be how to do this question with equivalent mass concept