Question

The amount of zinc required to produce 224 ml of H2 at stp on treatment with dilute h2so4 will be?

Answer 1

⭐️⭐️your answer ⭐️⭐️

Zinc reacts with sulfuric acid according to the following formula:

Zn + H2SO4 → ZnSO4 + H2

Therefore, 1 mole of zinc reacts to give 1 mole of hydrogen

Volume of 1 mole of hydrogen at STP is 22400 ml 

1 mole of Zn is 65 grams

Therefore 0.65 grams of zinc reacts to give 224 ml of hydrogen

⭐️⭐️hope this helps⭐️⭐️

Answer 2

Answer:

Explanation:

Zn + H2SO4=znso4 + h2

1. Mole Zn gives 1 mole of h2

22.4 l h2 = 65g Zn

.224l h2 = 65×.224/22.4

= 14.56/22.4

= .65g Zn

.65g Zn require to produce 224ml of h2