the amount of zinc required to produced 1.12ml of H2 at STP on treatment with dilute HCL will be? detailed answer
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Zn + 2HCl -----> H2 + ZnCl2Now,look at the equation carefully,
1 mole of Zn gives 1 mole of H2so,1.12 ml of H2 =1.12/22.4 = .05 moles of Zn
So, 0.05 moles of Zn is produced,
Amount produced = 0.05 * 65.4( molar mass of Zn) = 3.27g
Hence,amount of Zn produced is 3.27 g
1 mole of Zn gives 1 mole of H2so,1.12 ml of H2 =1.12/22.4 = .05 moles of Zn
So, 0.05 moles of Zn is produced,
Amount produced = 0.05 * 65.4( molar mass of Zn) = 3.27g
Hence,amount of Zn produced is 3.27 g
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