Question

The amplitude and time period of a simple pendulum bob are 0.05m and 2s respectively .then the maximum velocity of the bob is

Answer 1

T=2

w=2π/2

w=π

we know that

V=Aw

=0.05*π

=0.05π

hope this helps

(w=angular frequency)

Answer 2

The max restoring force for the pendulum is not -k A but rather -m g sin theta.

The angular frequency is pi / sec as already stated.

Then the maximum velocity must be w * L where L is the length of the string.

Since for a simple pendulum T = 2 pi (L/g)^1/2

T^2 / (4 pi*2) = L / g   then L = 4 * g / ( 4 pi^2) = .993 m

Then Vmax must be .993 * pi = 3.12 m/s.