The amplitude of a wave disturbance propagating in the positive x-direction is given by y = 1/(1 + x2 ) at time t = 0 and y = 1/[1 + (x – 1)2 ] at t = 2 seconds where x and y are in metres. the shape of the wave disturbance does not change during the propagation. the velocity of the wave is
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67
here,
y = 1/(1 + x²) at t = 0 sec
y = 1/[ 1 + (x - 1)²] at t = 2 sec
according to mathematics,[play with graph], if f(x) = f(x-1), it means shape of graph is same just change the position. graph shift right direction by 1 unit.
Here it is clear that the shape of wave doesn't change. also wave move in 2 sec , 1m in positive x direction.
so, wave moves 1 m in 2 sec .
so, velocity of wave = displacement of wave / time taken
= 1m/2sec = 0.5 m/sec
hence, velocity of wave = 0.5 m/s
y = 1/(1 + x²) at t = 0 sec
y = 1/[ 1 + (x - 1)²] at t = 2 sec
according to mathematics,[play with graph], if f(x) = f(x-1), it means shape of graph is same just change the position. graph shift right direction by 1 unit.
Here it is clear that the shape of wave doesn't change. also wave move in 2 sec , 1m in positive x direction.
so, wave moves 1 m in 2 sec .
so, velocity of wave = displacement of wave / time taken
= 1m/2sec = 0.5 m/sec
hence, velocity of wave = 0.5 m/s
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51
here is your answer bro ....
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