Question

the amplitude of the electric field of plane electromagnetic wave is 6.0×10-⁴ the amplitude of magnetic field will be​

Answer 1

Answer:

The amplitude of magnetic field is 2 × 10⁻¹² T

Explanation:

Given :

The amplitude of the electric field of plane electromagnetic wave is 6.0×10⁻⁴ V m⁻¹

To find :

the amplitude of magnetic field

Solution :

The relation between the amplitude of electric field and the amplitude of magnetic field of electromagnetic wave is given by,

 $\boxed{\sf c=\dfrac{E_o}{B_o}}$

where

c denotes velocity of light in vacuum

Eₒ denotes the amplitude of the electric field

Bₒ denotes the amplitude of the magnetic field

The velocity of the light in vacuum, c = 3 × 10⁸ m/s

magnitude of the electric field, Eₒ = 6 × 10⁻⁴ V m⁻¹

magnitude of the magnetic field, Bₒ = ?

Substitute the values,

 3 × 10⁸ = 6 × 10⁻⁴/Bₒ

Bₒ = 6 × 10⁻⁴/3 × 10⁸

Bₒ = 2 × 10⁻⁴⁻⁸

Bₒ = 2 × 10⁻¹² T

Therefore, the amplitude of magnetic field is 2 × 10⁻¹² T