Question

The amplitude of the magnetic field part of a harmonic electromagnetic wave in vacuum is B_0=510 nT. What is the amplitude of the electric field part of the wave?

Answer 1

Amplitude of the electric field of the wave is:

• The amplitude of the magnetic field part of a harmonic electromagnetic wave in vacuum = $B_0 = 510 nT = 510 * 10^{-9} T$

• Speed of light in vacuum, c = $3 * 10^8 m/s$

• Amplitude of electric field of the electromagnetic wave is $E=cB_0$

• From the equation, $E = 3* 10^8 * 510 * 10^{-9} = 153 N/C$

• Hence, the electric field part of the wave is 153 N/C.