Question

The % analysis by volume of product gas is H2 = 18.3%, CH2 = 3.4%, CO =25.4%, CO2 =5.1% and N2 = 47.8%. Calculate the volume of air required in m3 of the gas?​

Answer 1

Answer: 1.3643 m³

Explanation:

moles of O2 required

= 28.65

air required for 100 moles of fuel gas

= 28.65 × (100/21) = 136.43 mols

Therefore air required per m³ of gas

= (136.43/100) = 1.3643 m³

Answer 2

The volume of air required in $m^3$ of the gas is 1.3643.

• In the problem, we need to take out the required number of moles of oxygen.
• The moles of oxygen required for the analysis is 28.65 mol.
• Now, the air required for 100 moles of fuel gas is:

=$28.65*\frac{100}{21} \\136.43 mol$

• Now, the answer can be seen which is air required per m³ of gas:  (136.43/100)

= 1.3643 m³