The angal of elevation of the and bottom of a flagstaff fixed on a building are 45°and 30° respectively as observed ba a man standing on other end of a 15 m wide road find the haight of the flagstaff
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Let AB is the tower of height x m and BC is the flagstaff of height 10 m. Let D be the point from where the angles of elevation are 450 and
600 such that BDA = 450 and CDA = 600
In DAB, tan 450 = AB/AD
1 = x/AD AD = x
In DAC, tan 600 = AC/AD
3
= (10+x)/x3
x = 10+x
( 3 -1)x = 10
x = 10/( 3 - 1) = 10/(3- 1) x (3+ 1)/( 3+ 1)x = 5( 3+ 1)
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