Physics, asked by nemmojuvishnu, 1 month ago

The angel between the vectors a⃗=3i⃗-4j⃗ and b⃗ and b⃗=-2j⃗+3k⃗ is​

Answers

Answered by uniquegirl197
0

Answer:

Given:

a

=2

i

^

+

j

^

−3

k

^

and

b

=3

i

^

−2

j

^

k

^

a

.

b

=(2

i

^

+

j

^

−3

k

^

)(3

i

^

−2

j

^

k

^

)

=6−2+3=7....(1)

a

∣=

2

2

+1

2

+(−3)

2

=

14

....(2)

b

=

3

2

+(−2)

2

+(−1)

2

=

14

....(3)

cosθ=

a

∣.

b

a

.

b

=

14

14

7

=

2

1

cosθ=cos60

o

θ=60

o

Hence the required angle is 60

o

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