Question

the angel of elevation of the top of a building from a point on the ground which is 10m away from the building is found to be 45° . find the height of the building​

Answer 1

Answer:

In ΔBAP

tan30

o

=

AP

AB

⇒

3

1

=

x

10

x=10

3

m

Distance of building

Now,

In ΔPAD

tan45

o

=

AP

AD

1=

AP

AD

⇒x=AD=DB+BA

⇒10

3

=h+10

h=10

3

−10

=10(

3

−1)

h=10(1.732−1)

h=7.32m

Length of flag.

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Answer 2

Answer:

reply! telugu vasthundha?