Question

The angels of a quadiletral are in A.P. whose Common difference is 10. find the angles

Answer 1

hey mate

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here is ur answer

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let first angle is a°

we know that
the sum quadrilateral angle are 360
common difference= 10
then
first angle (a+10)
third angle (a+20)
fourth angle ( a+30)
4a+60= 360
4a=360-60
4a= 300
a=300/4
a=75°

so
1 angle = 75°
2 angle=85°
3 angle = 95°
4 angle= 105°

Answer 2

$\large\bf\color{red}{Hey\:Friend}$

let the first angle be a°
so, the next angle will be( a + 10 )°
third angle = ( a + 20 )°
forth angle = ( a + 30 )°

now, we know that the sum of all angles of a quadrilateral is 360°

so,

a + a + 10 + a + 20 + a + 30 = 360
4a + 60 = 360
4a = 300
a = 300/4
a = 75

so,
angle 1 = 75°
angle 2 = 85°
angle 3 = 95°
angle 4 = 105°