the angels of a triangle are in Ap whose common difference is 20 find the angels
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2
here is your answer mate ....
if those angles are in AP
then let smallest angle be x
thence a1=x
a2=x+20
a3=x+2(20)=x+40
adding all three eq....
x+x+20+x+40=180
3x=180-60
x=120/3=40
therefore.... angles are...
40,60,80 ans....
hope you have liked it so.... mark as brainliest
Answered by
0
40,60,80 are the angles
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