The angels of quadrilateral are ap and the greatest angle is double the least find angles of the quadrilateral in radian
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Step-by-step explanation:
Let the four angles of a quadrilateral are
(a−3d)
∘
, (a−d)
∘
, (a+d)
∘
and (a+3d)
∘
∴a−3d+a−d+a+d+a+3d=360
∘
⟹a=90
∘
But the greatest angle is double the least, i.e.,
a+3d=2×(a−3d)=2a−6d
∴9d=2a−a=a=90
∘
∴d=
9
90
=10
∘
∴ Least angle a−3d=90
∘
−3×10
∘
=60
∘
=
3
π
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