The angle ABC, if 3angle A=4 angleB=6AngleC, calculate angle A, B, C
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3 angleA=4 angleB
angleA=4/3 angleB________ eq 1
4 angleB=6 angleC
angleC=2/3 angleB________ eq 2
Now,
angleA+angleB+angleC=180
(Angle sum property of a triangle)
Putting value of angleA and angleC from equation 1 and 2 respectively,
4/3angleB+angleB+2/3angleB=180
angleB(4/3+1+2/3)=180
angleB((4+3+2)/3)=180
angleB(9/3)=180
angleB×3=180
angleB=60
angleA=4/3×60
angleA=80
angleC=2/3×60
angleC=40
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