Question

The angle at which both horizontal range and maximum height are equal..??​

Answer 1

Hope so it is helpful.........

Answer 2

Answer:

70 degree

Explanation:

Let θ be the angle of projection for which horizontal range and maximum height of a projectile are equal.Now,

H= u^2 sin^2 θ / 2g

R = u^2 sin^2θ / g

So, if H=R

then , u^2 sin^2 θ / 2g = u^2 sin^2 θ / g

or, sin^2 θ / 2 = sin2θ

or, sin^2 θ  =  2 (2 sinθ  cosθ )

or tan θ = 4

or, θ  = tan ^-1 ( 4) = 70 degree