Question

the angle at which the projectile body attains thw 86.6% of maximum range is?​

Answer 1

Answer:

I can't understand the question..

Answer 2

Answer:

30°

Explanation:

since the formula of maximum range is

Rmax=Vi²/g

so, we have given

R =86.6%Rmax

Vi²/g0.866 = Vi²Sin2@/g

0.866=Sin2@

Sin-¹(0.866) =2@

60/2=@

@ = 30°

where @ is theta (angle)