The angle between 6 ICAP + 3 j cap + 2 k cap and two ICAP - 2 j cap - k cap
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Given,
First vector is = 6i+3j+2k
Second vector is = 2i-2j-k
To find,
The angle between the two vectors.
Solution,
We can simply solve this mathematical problem by using the following mathematical process.
Let,
First vector = a
Second vector = b
|a| = √(6)²+(3)²+(2)² = √(36+9+4) = √49 = 7
|b| = √(2)²+(-2)²+(-1)² = √(4+4+1) = √9 = 3
a.b = (6)×(2)+(3)×(-2)+(2)×(-1) = 12-6-2 = 4
Let, angle between two vectors = θ
Now,
cos θ = (a.b)/(|a| |b|)
cos θ = 4/(3×7)
cos θ = 4/21
θ = cos⁻¹ 4/21
θ = 79.02°
Hence, the angle between two vectors is 79.02°
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