Question

The angle between (Abar cross Bbar) and (Bbar cross Abar) is​

Answer 1

Answer:

Given

A

×

B

=

B

×

A

⇒

A

×

B

−

B

×

A

=0

⇒

A

×

B

+

A

×

B

=0

⇒2(

A

×

B

)=0

⇒2

∣

∣

∣

∣

A

∣

∣

∣

∣

∣

∣

∣

∣

B

∣

∣

∣

∣

sinθ=0

∴sinθ=0

Hence, θ=π

Answer 2

Answer:

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