The angle between position vectors of the points P(2,2) & Q(-1,1) is
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90°
Explanation:
Taking,
Point O as origin,
P(2,2)=(x1 , y1)
Q(-1,1)= (x2, y2)
OP and OQ are the respective position vectors of P and Q
θ is the angle between OP and OQ
Angle between OP and x axis is θ1
tan θ1 = y1/x1 = 2/2 =1
tanθ1 = 1
Therefore θ1=45°
Angle between OQ and x axis is θ2
tan θ2 = y2/x2 = 1/-1 = -1
tan θ2 =-1
Therefore θ2 = 135°
θ= θ2-θ1
=135°-45°
=90°
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