The angle between the altitudes of a parallelogram. through the same vertex of an obtuse angle of the parallelogram is 50°. Find the angles of the parallelogram
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Answered by
8
In Quad. ABCD
CAB + ACD + CDE + DEA= 360°
CAB+ 90°+CDE + 90° = 360°
CAB+ CDE = 360° = 180°
D = 130°
A = D ( OPPOSITE SIDE OF PARALLEOGRAM)
NOW BD || AE (OPPOSITE SIDE OF PARRALEOGRAM)
D + E = 180°
130° + E = 180°
E = 180° - 130° = 50°
B = E = 50°
Answered by
8
Step-by-step explanation:
angle A = angle C = 60°
angle D = angle B = 120°
Hope it helps you
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