Question

the angle between the lines 3x-2y+5=0 and 2x+3y-7=0​

Answer 1

By data 2x + 3y – 4 = 0 … (1)

3x – 2y + 5 = 0 …… (2)

∴ Slope of (1) = -a/b

= -2/3 = m1

$slope \: of \: (2) = \frac{ - a}{b } = \frac{ - 3}{ - 2} = m 2$

$m1m2 = \frac{ - 2}{3} \times \frac{3}{2 } = - 1$

∴ the angle between the lines is 90°