Question

The angle between the pair of tangents drawn to the ellipse 3x2 + 2y2 = 5 from the point (1, 2) is

Answer 1

Answer:

Here, S = 3x2 + 2y2 -5 = 0

S1 = 3(1)2 + 2(2)2 -5 = 3 + 8 -5 = 6       [∵Point (1, 2)]

T = 3x.x1 + 2y.y1 -5

= 3x(l) + 2y(2) -5

= 3x + 4y -5

Now, use, SS1 = T2

(3x2 + 2y2 -5).6 = (3x + 4y -5)2

18x2 + 12y2 -30 = 9x2 + 16y2 + 24xy + 25 -30x -40y

⇒           9x2 -4y2 -24xy + 30x + 40y -55 = 0

Here, a = 9, b = -4 and h = -12

Answer 2

Answer:

it is very difficult