Question

The angle between the tangents to the circle x2+y2-2ax=0 from the point (3a,0) is

Answer 1

given=x is 3a.y is 0

x^2+y^2-2ax=0

(3a)^2+(0)^2-2a(3a)=0

9a^2-6a^2=0

3a^2=0

a^2=0÷3

a^2=0

a=0