the angle between the two vector a is equal to 3icap+4jcap+5kcap and vector b is aqual to 3icap + 4jcap-5kcap will be
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Answered by
1
Answer:
θ=76.5
Explanation:We're asked to find the angle between two vectors, given their unit vector notations.
To do this, we can use the equation
→A⋅→B=ABcosθ
rearranging to solve for angle,
θ:cosθ=→A⋅→BABθ=arccos
→A⋅→BAB
where→A.→B is the dot product of the two vectors, which is→A⋅→B=AxBx+AyBy+AzBz=(2)(1)+(3)(2)+(1)(−4)=4A and B are the magnitudes of vectors →A and →B, which areA=√22+32+12=√14b=√12+22(−4)2=√21therefore, we have θ=arccos(4√14√21)=arccos(47√6)=76.5o
Answered by
1
Answer:
0 degrees is the answer.
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