The angle between the
vector A=2i+3j +6k
and B=3i+2j-2k is
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Answer:
90 degree
Explanation:A=2i+3j +6k
B=3i+2j-2k
|A| =√(4+3+36) = 7
|B| =√(9+4+4) = √17
A.B = |A| |B| cosθ
(2i+3j +6k).( 3i+2j-2k) = 7*√17 cosθ
6+6-12=7*√17 cosθ
Cosθ = 0
θ = 90 degree
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