Physics, asked by amnamirbahar, 8 months ago

The angle between the
vector A=2i+3j +6k
and B=3i+2j-2k is​

Answers

Answered by kajalgargdei
1

Answer:

90 degree

Explanation:A=2i+3j +6k

B=3i+2j-2k

|A| =√(4+3+36) = 7

|B| =√(9+4+4) = √17

A.B = |A| |B| cosθ

(2i+3j +6k).( 3i+2j-2k) = 7*√17 cosθ

6+6-12=7*√17 cosθ

Cosθ = 0

θ = 90 degree

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