Question

the angle between the vector A and B is 60°.Given that A =B=1 CALCULATE B-A B+A?​

Answer 1

Answer:

Did you mean |B-A| and |B+A|? Without lack of generality, I start A at (0, 0) and end it at (1, 0), and start B at (0, 0) and end it at (.5, sqrt( 3) / 2). That being the case the vector B + A would start at (0, 0) and end at (1.5, sqrt( 3) / 2).

Then |A + B| = sqrt( 9/4 + 3/4) = sqrt( 12/4) = sqrt( 3) ~= 1.732

B - A would start at (0, 0) and end at (-.5, sqrt( 3) / 2).

Then |B - A| = sqrt( 3/4 + 1/4) = sqrt( 4/4) = 1

Explanation:

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