Question

The angle between the vectors 2i + j - 3 k and 3i
2j-k​

Answer 1

Answer:

D=cos^(-1)(11/14)

Step-by-step explanation:

A=(2,1,-3)

B=(3,2,-1)

D is the angle between A&B.

cosD=A.B/||A||.||B||

=(2,1,-3).(3,2,-1)/√(4+1+9).√(9+4+1)

=6+2+3/√14.√14

=11/14

THEREFORE,

D=cos^(-1)(11/14).