The angle between the vectors ( i - j ) and ( i + j ) is _ , where i and j are the unit vectors along X and Y axis
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Answer:
90°
Explanation:
Let A= i - j and B = i + j
| A | = √ { 1^2+ (-1)^2 = √2
| B | = √{1^2 + 1^2} = √2
A . B = | A | | B | cos ©
( i - j ) . ( i + j ) = √ 2 × √2 cos ©
i.i + j.i - j.i - j.j = 2 cos ©
1 - 1 = 2 cos ©
cos © = 0
cos © = cos 90°
and hence angle (©) = 90°
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