Question

The angle between two vectors of magnitude 12 and 18 units when their resultant is 24 unities

Answer 1

Answer:

R² = A² + B² + 2ABcos(θ)

24² = 12² + 18² + 2*12*18cos(θ)

We can do all the arithmetic or spot that 6² cancels out, giving:

4² = 2² + 3² + 2*2*3cos(θ)

16 = 13 + 12cos(θ)

cos(θ) = 3/12 = 0.25

θ = cos⁻¹0.25 = 75.5º..

Hope this helps u!!