Question

The angle between two vectors p and q is theta. Show by resolving these vectors into rectangular components that the magnitude of their resultant is (P^2+Q^2+2PQcos theta)^½.​

Answer 1

Explanation:

The angle between will be 0°.

If resultant is P-Q, then angle would be 180°

Formula is R² = P² + Q² - 2PQCos(theta)

R is resultant; theta is angle between P & Q; R,P,Q are in Mod value.

(P+Q)² = P² + Q² - 2PQCos(theta)

P² + Q² + 2PQ = P² + Q² - 2PQCos(theta)

2PQ = 2PQCos(theta)

Cos(theta) = 1

Cos(theta) = Cos0°

theta = 0°

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