Question

The angle between vector A and vector B is 60' what is the ratio of the vector A. VectorB and vrcto

Answer 1

Given that θ=60∘θ=60∘ is the angle between the vectors a⃗ a→ & b⃗ b→ then we have

|a⃗ ⋅b⃗ ||a⃗ ×b⃗ ||a→⋅b→||a→×b→|

=|a⃗ ||b⃗ |cosθ|a⃗ ||b⃗ |sinθ=|a→||b→|cos⁡θ|a→||b→|sin⁡θ

=cotθ=cot⁡θ

=cot60∘=cot⁡60∘

=
$1 \div \sqrt{3 }$