The angle between vector i and vector (i+j+k) is,symbols having their usual meaning,
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cos thera=root (1^2+1^2+1^2)/1=root3
thers=cos^-1 (root3)=
thers=cos^-1 (root3)=
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let Angle between these vectors be =>Q
DOT product of given vectors => 1 unit
so, Let above vectors be A and B
so,A.B =(|A| * |B|) *cos Q
so,cos Q= (A.B )/|A| * |B|
cos Q = 1 / √3
so ,Q =cos-¹ (1/√3)
Thumbs Up!!
DOT product of given vectors => 1 unit
so, Let above vectors be A and B
so,A.B =(|A| * |B|) *cos Q
so,cos Q= (A.B )/|A| * |B|
cos Q = 1 / √3
so ,Q =cos-¹ (1/√3)
Thumbs Up!!
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