Question

The angle bisectors of angle b and c of triangle abc meet at point o . P.t angle boc= 90 ° + angle a / 2

Answer 1

Answer:

In tri abc

A+2obc+2ocb=180°

2(A/2+obc+ ocb)=180

A/2+obc+ocb=90°

obc+ocb=90°-A/2. ---1

Now

in tri boc

boc+obc+ocb=180°

boc+90°-A/2=180°. ---[From 1]

boc=180°-90°+A/2

boc=90°+A/2 HP