The angle bw two vectors (I cap + j cap) and ( j cap + k cap) is:
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Hello,
Let
a^ =I cap + j cap
b^ =j cap + k cap, Be two vectors
We know that,
Dot product of two vectors is,
a.b=|a||b|cos(a, b)
From this,
cos(a, b) =a.b/(|a||b|)
a.b=(I cap + j cap).(j cap + k cap)
=1
|a|=sqrt(1^2+1^2)
=sqrt(2)
|b|=sqrt(1^2+1^2)
=sqrt(2)
Now,
cos(a, b) =a.b/(|a||b|)
=1/sqrt(2) ^2
=1/2
Angle between the two vectors is given by the inverse of cosine function.
Angle =Cos^-1(1/2)
= 60°
I hope this is clear!
desiboy84:
Correct✅✔ answer
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