Question

the angle elevation of top of building from a point on the ground which 20m away from the foot tof the building is 60. find the height of building​

Answer 1

Step-by-step explanation:

Let the distance between point of observation and foot of tower BC=20m

Height of tower AB = H

Angle of elevation of top of tower θ=60°  

Now from figure ΔABC

We know that, ΔABC is a right angle triangle.

tanθ = $\frac{AB}{BC}$  

tan 60° = $\frac{h}{20}$  

⇒  $\frac{h}{20}$ =  3  

⇒h=20√3  m.

Therefore, height of tower=20√3  m

Answer 2

Answer:

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