the angle exceeds its complementary angle by 30degree find the angle
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Let the angle be x
another angle be x+30
x+x+30=90
2x=60
x=30
another angle=30+30=60
another angle be x+30
x+x+30=90
2x=60
x=30
another angle=30+30=60
Answered by
0
Let the complementary angle be x
Then x+x+30=90
2x+30=90
2x=90-30
2x=60
x=60/2
x=30
so,x+30=60
THE ANGLE IS 60^DEGREE
HOPE IT HELPS YOU
THANK YOU
Then x+x+30=90
2x+30=90
2x=90-30
2x=60
x=60/2
x=30
so,x+30=60
THE ANGLE IS 60^DEGREE
HOPE IT HELPS YOU
THANK YOU
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