Question

the angle if elevation of the top of a tower from a point on the ground,which is 30m away from the foot of the tower, is 30°. find the height of the tower. ​

Answer 1

Step-by-step explanation:

tan 30° = AC / BC

then do it yourself

Answer 2

Answer:

17.320 m

Step-by-step explanation:

Refer the attached figure

AB = Height of tower

BC = 30 m

∠ACB = 30°

InΔABC

$Tan \theta=\frac{Perpendicular}{Base}$

$Tan30^{\circ}=\frac{AB}{BC}$

$30 \times \frac{1}{\sqrt{3}} = AB$

17.320 = AB

Hence The height of tower is 17.320 m